What is the general solution for 4cos^2(x)-2=1 ?

The general solution for 4cos^2(x)-2=1 is x= pi/6+2pin,x=(11pi)/6+2pin,x=(5pi)/6+2pin,x=(7pi)/6+2pin

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4cos^2(x)-2=1

4 cos^{2} (x) - 2 = 1

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solution steps

4 cos^{2} (x) - 2 = 1

Solve by substitution

cos (x) = \frac{3}{2}, cos (x) = - \frac{3}{2}

cos (x) = \frac{3}{2} : x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

cos (x) = - \frac{3}{2} : x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

θ, x = r cos (θ)

1 + sec^{2} (x) = 3

2 cos (a) sin (a) - 4 cos (a) + 6 sin (a) - 12 = 0

cos (x) = \frac{83}{92}

sin (\frac{π}{4} x) = 1

What is the general solution for 4cos^2(x)-2=1 ?
The general solution for 4cos^2(x)-2=1 is x= pi/6+2pin,x=(11pi)/6+2pin,x=(5pi)/6+2pin,x=(7pi)/6+2pin