What is the general solution for sqrt(3)+2sin(β)=0 ?

The general solution for sqrt(3)+2sin(β)=0 is β=(4pi)/3+2pin,β=(5pi)/3+2pin

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sqrt(3)+2sin(β)=0

3 + 2 sin (β) = 0

β = \frac{4 π}{3} + 2 πn, β = \frac{5 π}{3} + 2 πn

Solution steps

3 + 2 sin (β) = 0

Move

3

to the right side

2 sin (β) = - 3

Divide both sides by

2

sin (β) = - \frac{3}{2}

General solutions for

sin (β) = - \frac{3}{2}

β = \frac{4 π}{3} + 2 πn, β = \frac{5 π}{3} + 2 πn

sin (2 t) = \frac{3}{2}

cos (θ) = \frac{5}{7}, sin (θ) > 0

cos (t) = - \frac{1}{2}

tan (θ) = \frac{2 3}{2}

sec^{2} (x) + 2 tan (x) = 0

What is the general solution for sqrt(3)+2sin(β)=0 ?
The general solution for sqrt(3)+2sin(β)=0 is β=(4pi)/3+2pin,β=(5pi)/3+2pin