What is the general solution for 2cos(θ)-3=-2 ?

The general solution for 2cos(θ)-3=-2 is θ= pi/3+2pin,θ=(5pi)/3+2pin

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2cos(θ)-3=-2

2 cos (θ) - 3 = - 2

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

2 cos (θ) - 3 = - 2

Move

3

to the right side

2 cos (θ) = 1

Divide both sides by

2

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

2 sin (\frac{1}{2} x) = 1, 0^{\circ} \leq x \leq 1 2^{\circ}

2 sin (\frac{π}{4} + x) \cdot sin (\frac{π}{4} - x) + sin^{2} (x) = 0

(2 sin (x) - 1) (cos (x) + 1) = 0

7 sin^{2} (x) - 6 = - 3 sin^{2} (x)

tan (b) = 4

What is the general solution for 2cos(θ)-3=-2 ?
The general solution for 2cos(θ)-3=-2 is θ= pi/3+2pin,θ=(5pi)/3+2pin