What is the general solution for 5tan(θ)+3=0 ?

The general solution for 5tan(θ)+3=0 is θ=-0.54041…+pin

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5tan(θ)+3=0

5 tan (θ) + 3 = 0

θ = - 0.54041 \dots + πn

Degrees

θ = - 30.96375 \dots^{\circ} + 18 0^{\circ} n

Solution steps

5 tan (θ) + 3 = 0

Move

3

to the right side

5 tan (θ) + 3 = 0

Subtract

3

from both sides

5 tan (θ) + 3 - 3 = 0 - 3

Simplify

5 tan (θ) = - 3

5 tan (θ) = - 3

Divide both sides by

5

5 tan (θ) = - 3

Divide both sides by

5

\frac{5 tan ( θ )}{5} = \frac{- 3}{5}

Simplify

tan (θ) = - \frac{3}{5}

tan (θ) = - \frac{3}{5}

Apply trig inverse properties

tan (θ) = - \frac{3}{5}

General solutions for

tan (θ) = - \frac{3}{5}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{3}{5}) + πn

θ = arctan (- \frac{3}{5}) + πn

Show solutions in decimal form

θ = - 0.54041 \dots + πn

sin (θ) = - \frac{4}{7}, π < θ < \frac{3 π}{2}, cos (2 θ)

tan (θ) = - \frac{2}{5}

(tan (x) - 1) (3 tan (x) + 1) = 0

sec (2 x) + 1 = 0

sin (θ) = - \frac{4}{7}

What is the general solution for 5tan(θ)+3=0 ?
The general solution for 5tan(θ)+3=0 is θ=-0.54041…+pin