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cos(x)(2sin(x)+1)=0,0<= x<= 2pi

Solution

cos (x) (2 sin (x) + 1) = 0, 0 \leq x \leq 2 π

Solution

x = \frac{π}{2}, x = \frac{3 π}{2}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

+1

Solution steps

cos (x) (2 sin (x) + 1) = 0, 0 \leq x \leq 2 π

Solving each part separately

cos (x) = 0 or 2 sin (x) + 1 = 0

cos (x) = 0, 0 \leq x \leq 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

2 sin (x) + 1 = 0, 0 \leq x \leq 2 π : x = \frac{7 π}{6}, x = \frac{11 π}{6}

Combine all the solutions

x = \frac{π}{2}, x = \frac{3 π}{2}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

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