What is the general solution for cos^2(θ)-cos(θ)-6=0 ?

The general solution for cos^2(θ)-cos(θ)-6=0 is No Solution for θ\in\mathbb{R}

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cos^2(θ)-cos(θ)-6=0

cos^{2} (θ) - cos (θ) - 6 = 0

No Solution for θ \in R

Solution steps

cos^{2} (θ) - cos (θ) - 6 = 0

Solve by substitution

cos (θ) = 3, cos (θ) = - 2

cos (θ) = 3 :

No Solution

cos (θ) = - 2 :

No Solution

Combine all the solutions

No Solution for θ \in R

x, 0 = 1 + cos (x)

1 = 2 sin (2 x)

3 cos (θ) = 2

cot (t) = - \frac{1}{3}

sin (2 x) = - 2 sin (x)

What is the general solution for cos^2(θ)-cos(θ)-6=0 ?
The general solution for cos^2(θ)-cos(θ)-6=0 is No Solution for θ\in\mathbb{R}