What is the general solution for 2cos(x)-sqrt(3)=0,0<= x<= 2pi ?

The general solution for 2cos(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(x)-sqrt(3)=0,0<= x<= 2pi

2 cos (x) - 3 = 0, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}

Solution steps

2 cos (x) - 3 = 0, 0 \leq x \leq 2 π

Move

3

to the right side

2 cos (x) = 3

Divide both sides by

2

cos (x) = \frac{3}{2}

General solutions for

cos (x) = \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}

sec^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

3 cos (\frac{x}{2}) + 3 = cos (\frac{x}{2})

(tan (θ) + 1) (tan (θ) - 3) = 0

\frac{2}{3} cos (3 x) = 1

2 cos^{2} (x) - 2 sin^{2} (x) = 0

What is the general solution for 2cos(x)-sqrt(3)=0,0<= x<= 2pi ?
The general solution for 2cos(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6