What is the general solution for 6+12sin(θ)=0 ?

The general solution for 6+12sin(θ)=0 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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6+12sin(θ)=0

6 + 12 sin (θ) = 0

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

6 + 12 sin (θ) = 0

Move

6

to the right side

12 sin (θ) = - 6

Divide both sides by

12

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

t, cos (2 t) = sin (t)

tan (x) = 1.8

tan (x) = 1.6

cos (8 x) (2 cos (x) + 1) = 0

cos (θ) = \frac{1}{2}, 0 \leq θ \leq 2 π

What is the general solution for 6+12sin(θ)=0 ?
The general solution for 6+12sin(θ)=0 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin