What is the general solution for cos(θ)= 1/2 ,0<= θ<= 2pi ?

The general solution for cos(θ)= 1/2 ,0<= θ<= 2pi is θ= pi/3 ,θ=(5pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)= 1/2 ,0<= θ<= 2pi

cos (θ) = \frac{1}{2}, 0 \leq θ \leq 2 π

θ = \frac{π}{3}, θ = \frac{5 π}{3}

Solution steps

cos (θ) = \frac{1}{2}, 0 \leq θ \leq 2 π

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{3}, θ = \frac{5 π}{3}

sin (3 π x) - 1 = 0

sin (x) = 12

2 sin (x) + sin^{2} (x) = 0

sec (θ) = 1.10413

0 = - 4 cos (3 x) + 22

What is the general solution for cos(θ)= 1/2 ,0<= θ<= 2pi ?
The general solution for cos(θ)= 1/2 ,0<= θ<= 2pi is θ= pi/3 ,θ=(5pi)/3