What is the general solution for 2sin(x)+sin^2(x)=0 ?

The general solution for 2sin(x)+sin^2(x)=0 is x=2pin,x=pi+2pin

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2sin(x)+sin^2(x)=0

2 sin (x) + sin^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin (x) + sin^{2} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - 2

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 2 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

sec (θ) = 1.10413

0 = - 4 cos (3 x) + 22

6 sin (x) = 0

2 sin^{2} (θ) + cos (θ) = 0, 0 \leq θ \leq 2 π

cos (a) - 1 = 2 cos (a)

What is the general solution for 2sin(x)+sin^2(x)=0 ?
The general solution for 2sin(x)+sin^2(x)=0 is x=2pin,x=pi+2pin