What is the general solution for tan^2(x)-1=0,0<= x<= pi/2 ?

The general solution for tan^2(x)-1=0,0<= x<= pi/2 is x= pi/4

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tan^2(x)-1=0,0<= x<= pi/2

tan^{2} (x) - 1 = 0, 0 \leq x \leq \frac{π}{2}

x = \frac{π}{4}

Solution steps

tan^{2} (x) - 1 = 0, 0 \leq x \leq \frac{π}{2}

Solve by substitution

tan (x) = 1, tan (x) = - 1

tan (x) = 1, 0 \leq x \leq \frac{π}{2} : x = \frac{π}{4}

tan (x) = - 1, 0 \leq x \leq \frac{π}{2} :

No Solution

Combine all the solutions

x = \frac{π}{4}

10 cos (B) + 6 = 4 cos (B) + 4

2 sin (x) + 2 sin (x) tan (x) = 0

y, x = x (1 + tan (y))

- 9 cos^{2} (θ) + sin (θ) + 11 = - sin (θ) + 2

sin (θ) = 1 - 2 cos (θ)

What is the general solution for tan^2(x)-1=0,0<= x<= pi/2 ?
The general solution for tan^2(x)-1=0,0<= x<= pi/2 is x= pi/4