What is the general solution for cos^2(x)-1/4 =0,0<= x<= 2pi ?

The general solution for cos^2(x)-1/4 =0,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3 ,x=(2pi)/3 ,x=(4pi)/3

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cos^2(x)-1/4 =0,0<= x<= 2pi

cos^{2} (x) - \frac{1}{4} = 0, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}

Solution steps

cos^{2} (x) - \frac{1}{4} = 0, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - \frac{1}{2}

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{3}, x = \frac{5 π}{3}

cos (x) = - \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{2 π}{3}, x = \frac{4 π}{3}

Combine all the solutions

x = \frac{π}{3}, x = \frac{5 π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}

tan (6 x) = 1

sin (2 x + 7) = cos (4 x - 7)

x, cot (x) = 2

- 2 sin^{2} (x) + sin (x) = 0

2 sin (x + 6 0^{\circ}) = cos (x + 3 0^{\circ})

What is the general solution for cos^2(x)-1/4 =0,0<= x<= 2pi ?
The general solution for cos^2(x)-1/4 =0,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3 ,x=(2pi)/3 ,x=(4pi)/3