What is the general solution for -2sin^2(x)+sin(x)=0 ?

The general solution for -2sin^2(x)+sin(x)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin

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-2sin^2(x)+sin(x)=0

- 2 sin^{2} (x) + sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

- 2 sin^{2} (x) + sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = \frac{1}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

2 sin (x + 6 0^{\circ}) = cos (x + 3 0^{\circ})

cot^{2} (θ) - 3 csc (θ) = - 3

tan^{3} (x) = \frac{1}{3} tan (x)

cos^{2} (x) = \frac{2}{3}

5 ∣ tan (x) ∣ = 5

What is the general solution for -2sin^2(x)+sin(x)=0 ?
The general solution for -2sin^2(x)+sin(x)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin