What is the general solution for 5|tan(x)|=5 ?

The general solution for 5|tan(x)|=5 is x=(3pi)/4+pin,x= pi/4+pin

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5|tan(x)|=5

5 ∣ tan (x) ∣ = 5

x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

Solution steps

5 ∣ tan (x) ∣ = 5

Solve by substitution

tan (x) = - 1 or tan (x) = 1

tan (x) = - 1 : x = \frac{3 π}{4} + πn

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

3 arccos (x) = 2

cos (4 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

3 csc^{2} (x) + 1.5 cot (x) = 15

sin (y) = cos (y)

\frac{cos ( x )}{sin ( x )} = 2

What is the general solution for 5|tan(x)|=5 ?
The general solution for 5|tan(x)|=5 is x=(3pi)/4+pin,x= pi/4+pin