What is the general solution for cos^2(x)sin(x)=sin(x) ?

The general solution for cos^2(x)sin(x)=sin(x) is x=2pin,x=pi+2pin

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cos^2(x)sin(x)=sin(x)

cos^{2} (x) sin (x) = sin (x)

x = 2 πn, x = π + 2 πn

Solution steps

cos^{2} (x) sin (x) = sin (x)

Subtract

sin (x)

from both sides

cos^{2} (x) sin (x) - sin (x) = 0

Factor

cos^{2} (x) sin (x) - sin (x) : sin (x) (cos (x) + 1) (cos (x) - 1)

sin (x) (cos (x) + 1) (cos (x) - 1) = 0

Solving each part separately

sin (x) = 0 or cos (x) + 1 = 0 or cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

cos (x) + 1 = 0 : x = π + 2 πn

cos (x) - 1 = 0 : x = 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

sin (2 x - 0.35) = cos (3 x)

2 cos^{2} (x) - 15 cos (x) + 7 = 0

sec (θ) = - \frac{5}{4}

sin^{2} (x) - 4 sin (x) + 1 = 0

6 sin (2 x) + 2 sin (x) = 0

What is the general solution for cos^2(x)sin(x)=sin(x) ?
The general solution for cos^2(x)sin(x)=sin(x) is x=2pin,x=pi+2pin