What is the general solution for 6arccos(4x)=5pi ?

The general solution for 6arccos(4x)=5pi is x=-(sqrt(3))/8

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6arccos(4x)=5pi

6 arccos (4 x) = 5 π

x = - \frac{3}{8}

Solution steps

6 arccos (4 x) = 5 π

Divide both sides by

6

arccos (4 x) = \frac{5 π}{6}

Apply trig inverse properties

4 x = - \frac{3}{2}

Solve

4 x = - \frac{3}{2} : x = - \frac{3}{8}

x = - \frac{3}{8}

2 sin^{2} (x) - cos (x) = 1, 0 \leq x \leq 2 π

cos (θ) = - \frac{π}{2}

4 sin (t^{2}) - 1 = 1

sec (x) + 4 = 4 sec (x)

cos (x) + 2 cos (2 x) = 0

What is the general solution for 6arccos(4x)=5pi ?
The general solution for 6arccos(4x)=5pi is x=-(sqrt(3))/8