What is the general solution for 2-4sin(θ)=0 ?

The general solution for 2-4sin(θ)=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2-4sin(θ)=0

2 - 4 sin (θ) = 0

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

2 - 4 sin (θ) = 0

Move

2

to the right side

- 4 sin (θ) = - 2

Divide both sides by

- 4

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

2 cos (t) = 1, - π \leq t \leq π

tan (\frac{x}{3}) = 1, 0 \leq x \leq 2 π

4 sin (x) = sin (x) tan (x)

cos (x) = 0.707

4 cos^{2} (x) - 4 cos (x) - 3 = 0

What is the general solution for 2-4sin(θ)=0 ?
The general solution for 2-4sin(θ)=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin