What is the general solution for -1/2 =sin(2x) ?

The general solution for -1/2 =sin(2x) is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin

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-1/2 =sin(2x)

- \frac{1}{2} = sin (2 x)

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

Solution steps

- \frac{1}{2} = sin (2 x)

Switch sides

sin (2 x) = - \frac{1}{2}

General solutions for

sin (2 x) = - \frac{1}{2}

2 x = \frac{7 π}{6} + 2 πn, 2 x = \frac{11 π}{6} + 2 πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

Solve

2 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{12} + πn

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

72 (- 3 cos^{2} (x) sin^{2} (x) + cos^{4} (x)) = 0

sin (\frac{x}{5}) = \frac{2}{2}

x, sin (x) = 0.6

4 cos (2 t) = 4 sin^{2} (t) + 1

tan^{2} (θ) + 2 tan (θ) = - 1

What is the general solution for -1/2 =sin(2x) ?
The general solution for -1/2 =sin(2x) is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin