What is the general solution for (10cos(2t+pi/6))=0 ?

The general solution for (10cos(2t+pi/6))=0 is t=pin+pi/6 ,t=pin+(2pi)/3

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(10cos(2t+pi/6))=0

(10 cos (2 t + \frac{π}{6})) = 0

t = πn + \frac{π}{6}, t = πn + \frac{2 π}{3}

Solution steps

(10 cos (2 t + \frac{π}{6})) = 0

Divide both sides by

10

cos (2 t + \frac{π}{6}) = 0

General solutions for

cos (2 t + \frac{π}{6}) = 0

2 t + \frac{π}{6} = \frac{π}{2} + 2 πn, 2 t + \frac{π}{6} = \frac{3 π}{2} + 2 πn

Solve

2 t + \frac{π}{6} = \frac{π}{2} + 2 πn : t = πn + \frac{π}{6}

Solve

2 t + \frac{π}{6} = \frac{3 π}{2} + 2 πn : t = πn + \frac{2 π}{3}

t = πn + \frac{π}{6}, t = πn + \frac{2 π}{3}

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What is the general solution for (10cos(2t+pi/6))=0 ?
The general solution for (10cos(2t+pi/6))=0 is t=pin+pi/6 ,t=pin+(2pi)/3