What is the general solution for sin^2(x)-3=2sin(x) ?

The general solution for sin^2(x)-3=2sin(x) is x=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)-3=2sin(x)

sin^{2} (x) - 3 = 2 sin (x)

x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - 3 = 2 sin (x)

Solve by substitution

sin (x) = 3, sin (x) = - 1

sin (x) = 3 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

tan^{2} (x) - (3 + 1) tan (x) + 3 = 0

6 cos (θ) = 3

4 cos^{3} (x) = cos (x)

csc^{5} (θ) - 4 csc (θ) = 0

16 sin^{2} (x) - 4 = 0

What is the general solution for sin^2(x)-3=2sin(x) ?
The general solution for sin^2(x)-3=2sin(x) is x=(3pi)/2+2pin