What is the general solution for cos(x)=cos(1) ?

The general solution for cos(x)=cos(1) is x=1+2pin,x=2pi-1+2pin

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cos(x)=cos(1)

cos (x) = cos (1)

x = 1 + 2 πn, x = 2 π - 1 + 2 πn

Degrees

x = 57.29577 \dots^{\circ} + 36 0^{\circ} n, x = 302.70422 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = cos (1)

Apply trig inverse properties

cos (x) = cos (1)

General solutions for

cos (x) = cos (1)

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (cos (1)) + 2 πn, x = 2 π - arccos (cos (1)) + 2 πn

x = arccos (cos (1)) + 2 πn, x = 2 π - arccos (cos (1)) + 2 πn

Show solutions in decimal form

x = 1 + 2 πn, x = 2 π - 1 + 2 πn

sin^{2} (2 θ) = 0

y, x = 2 sec (y)

tan (π + c) = 1

8 sin^{2} (x) = 8 cos^{2} (x)

sin (x) = \frac{6}{8}

What is the general solution for cos(x)=cos(1) ?
The general solution for cos(x)=cos(1) is x=1+2pin,x=2pi-1+2pin