What is the general solution for 2pi+6arccos(2-x)=0 ?

The general solution for 2pi+6arccos(2-x)=0 is No Solution for x\in\mathbb{R}

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2pi+6arccos(2-x)=0

2 π + 6 arccos (2 - x) = 0

No Solution for x \in R

Solution steps

2 π + 6 arccos (2 - x) = 0

Move

2 π

to the right side

6 arccos (2 - x) = - 2 π

Divide both sides by

6

arccos (2 - x) = - \frac{π}{3}

0 \leq arccos (x) \leq π

No Solution for x \in R

tan (x) = \frac{12}{4}

1 - 2 cos (θ) = 0

3 tan (3 x) - 1 = 0, 0 \leq x \leq 2 π

- 2 sin^{2} (x) = 0

x, p + 3 q = 5 z + tan (y - 3 x)

What is the general solution for 2pi+6arccos(2-x)=0 ?
The general solution for 2pi+6arccos(2-x)=0 is No Solution for x\in\mathbb{R}