What is the general solution for sin^2(x)+cos(x)-1=0 ?

The general solution for sin^2(x)+cos(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)+cos(x)-1=0

sin^{2} (x) + cos (x) - 1 = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn

Solution steps

sin^{2} (x) + cos (x) - 1 = 0

Rewrite using trig identities

cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = 0, cos (x) = 1

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn

12 tan (x) + 5 = 5 tan (x) + 5

4 cos (x) + 3 sin (x) = 0

2 sin (4 x) - 1 = 0, 0 < x \leq 2

5 cos (θ) = - 5 sin (- θ)

cos (x) - 2 sin (x) cos (x) = 0, 0 \leq x \leq 2 π

What is the general solution for sin^2(x)+cos(x)-1=0 ?
The general solution for sin^2(x)+cos(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin