What is the general solution for 8sin(b)+1=sin(b)+1 ?

The general solution for 8sin(b)+1=sin(b)+1 is b=2pin,b=pi+2pin

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8sin(b)+1=sin(b)+1

8 sin (b) + 1 = sin (b) + 1

b = 2 πn, b = π + 2 πn

Solution steps

8 sin (b) + 1 = sin (b) + 1

Solve by substitution

sin (b) = 0

sin (b) = 0 : b = 2 πn, b = π + 2 πn

Combine all the solutions

b = 2 πn, b = π + 2 πn

7 cos (3 x) = 7

cos^{2} (θ) = sin^{2} (θ) + 1

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) - 1 = 0

\frac{1}{2} sin (x) = - \frac{3}{4}

cos^{2} (x) + 3 cos (x) - 4 = 0

What is the general solution for 8sin(b)+1=sin(b)+1 ?
The general solution for 8sin(b)+1=sin(b)+1 is b=2pin,b=pi+2pin