What is the general solution for 2sin(x)-sqrt(3)=0,0<= x<= 2pi ?

The general solution for 2sin(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/3 ,x=(2pi)/3

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2sin(x)-sqrt(3)=0,0<= x<= 2pi

2 sin (x) - 3 = 0, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

Solution steps

2 sin (x) - 3 = 0, 0 \leq x \leq 2 π

Move

3

to the right side

2 sin (x) = 3

Divide both sides by

2

sin (x) = \frac{3}{2}

General solutions for

sin (x) = \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

cos (θ) = cot (θ)

8 cos (x) + 4 sin (2 x) = 0

sin (x) = - \frac{4}{5}, cos (x) < 0, cos (\frac{x}{2})

1 + sin (x) - 2 sin^{2} (x) = 0

y, z = e^{- x} sin (x + 2 y)

What is the general solution for 2sin(x)-sqrt(3)=0,0<= x<= 2pi ?
The general solution for 2sin(x)-sqrt(3)=0,0<= x<= 2pi is x= pi/3 ,x=(2pi)/3