What is the general solution for sin(x)=-4/5 ,cos(x)<0,cos(x/2) ?

The general solution for sin(x)=-4/5 ,cos(x)<0,cos(x/2) is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)=-4/5 ,cos(x)<0,cos(x/2)

sin (x) = - \frac{4}{5}, cos (x) < 0, cos (\frac{x}{2})

No Solution for x \in R

Solution steps

sin (x) = - \frac{4}{5}, cos (x) < 0, cos (\frac{x}{2})

Apply trig inverse properties

sin (x) = - \frac{4}{5}

General solutions for

sin (x) = - \frac{4}{5}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{4}{5}) + 2 πn, x = π + arcsin (\frac{4}{5}) + 2 πn

x = arcsin (- \frac{4}{5}) + 2 πn, x = π + arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

cos (x) < 0

No Solution for x \in R

1 + sin (x) - 2 sin^{2} (x) = 0

y, z = e^{- x} sin (x + 2 y)

3 sin (θ) - 2 sin^{2} (θ) = 0

3 tan (\frac{x}{3}) + 3 = 0

0 = 2 sin (2 x)

What is the general solution for sin(x)=-4/5 ,cos(x)<0,cos(x/2) ?
The general solution for sin(x)=-4/5 ,cos(x)<0,cos(x/2) is No Solution for x\in\mathbb{R}