What is the general solution for cos(2x)=-1/2 ,0<= x<= 2pi ?

The general solution for cos(2x)=-1/2 ,0<= x<= 2pi is x= pi/3 ,x=(2pi)/3 ,x=(4pi)/3 ,x=(5pi)/3

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cos(2x)=-1/2 ,0<= x<= 2pi

cos (2 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = \frac{5 π}{3}

Solution steps

cos (2 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

General solutions for

cos (2 x) = - \frac{1}{2}

2 x = \frac{2 π}{3} + 2 πn, 2 x = \frac{4 π}{3} + 2 πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

Solve

2 x = \frac{4 π}{3} + 2 πn : x = \frac{2 π}{3} + πn

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = \frac{5 π}{3}

x, 1 + sin (2 x) = 0

- cos (θ) + 2 cos^{2} (θ) = 0

sin (x) = 2 sin (x) + 1

4 cosh (x) - sinh (x) = 8

- 53 cot (θ) + 1 = 16

What is the general solution for cos(2x)=-1/2 ,0<= x<= 2pi ?
The general solution for cos(2x)=-1/2 ,0<= x<= 2pi is x= pi/3 ,x=(2pi)/3 ,x=(4pi)/3 ,x=(5pi)/3