What is the general solution for arcsin(x+1)=-0.5 ?

The general solution for arcsin(x+1)=-0.5 is x=-sin(1/2)-1

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arcsin(x+1)=-0.5

arcsin (x + 1) = - 0.5

x = - sin (\frac{1}{2}) - 1

Solution steps

arcsin (x + 1) = - 0.5

Apply trig inverse properties

arcsin (x + 1) = - 0.5

arcsin (x) = a \Rightarrow x = sin (a)

x + 1 = sin (- 0.5)

sin (- 0.5) = - sin (\frac{1}{2})

sin (- 0.5)

= sin (- \frac{1}{2})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{1}{2}) = - sin (\frac{1}{2})

= - sin (\frac{1}{2})

x + 1 = - sin (\frac{1}{2})

x + 1 = - sin (\frac{1}{2})

Solve

x + 1 = - sin (\frac{1}{2}) : x = - sin (\frac{1}{2}) - 1

x + 1 = - sin (\frac{1}{2})

Move

1

to the right side

x + 1 = - sin (\frac{1}{2})

Subtract

1

from both sides

x + 1 - 1 = - sin (\frac{1}{2}) - 1

Simplify

x = - sin (\frac{1}{2}) - 1

x = - sin (\frac{1}{2}) - 1

x = - sin (\frac{1}{2}) - 1

sin (θ) = - 0.8

cos (x^{2}) + sin (x^{2}) = 1

cos (\frac{x}{3} - \frac{π}{4}) = \frac{1}{2}

12 sin^{2} (x) + 7 cos (x) - 13 = 0

tan (3 x - π) = 1

What is the general solution for arcsin(x+1)=-0.5 ?
The general solution for arcsin(x+1)=-0.5 is x=-sin(1/2)-1