What is the general solution for 2cos^2(x)+cos(x)-10=0 ?

The general solution for 2cos^2(x)+cos(x)-10=0 is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+cos(x)-10=0

2 cos^{2} (x) + cos (x) - 10 = 0

No Solution for x \in R

Solution steps

2 cos^{2} (x) + cos (x) - 10 = 0

Solve by substitution

cos (x) = 2, cos (x) = - \frac{5}{2}

cos (x) = 2 :

No Solution

cos (x) = - \frac{5}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

a, 9 0^{\circ} = 18 0^{\circ} - 2 \cdot arccos (\frac{2 a}{c})

cos (x) = \frac{π}{4}

cot (x) = \frac{3}{7}, cos (x) > 0

4 tanh (x) - \frac{1}{cosh ( x )} = 1

2 sin (θ) cos (θ) = sin (θ)

What is the general solution for 2cos^2(x)+cos(x)-10=0 ?
The general solution for 2cos^2(x)+cos(x)-10=0 is No Solution for x\in\mathbb{R}