What is the general solution for cos(θ)=-(sqrt(11))/6 ?

The general solution for cos(θ)=-(sqrt(11))/6 is θ=2.15648…+2pin,θ=-2.15648…+2pin

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cos(θ)=-(sqrt(11))/6

cos (θ) = - \frac{11}{6}

θ = 2.15648 \dots + 2 πn, θ = - 2.15648 \dots + 2 πn

Solution steps

cos (θ) = - \frac{11}{6}

Apply trig inverse properties

θ = arccos (- \frac{11}{6}) + 2 πn, θ = - arccos (- \frac{11}{6}) + 2 πn

Show solutions in decimal form

θ = 2.15648 \dots + 2 πn, θ = - 2.15648 \dots + 2 πn

sin^{2} (x) - csc^{2} (x) = tan^{2} (x) - cot^{2} (x)

sin (x) = \frac{53}{54}

2 sin^{2} (x) + sin (x) - 3 = 0

(2 cos (x) - 1) sin (x) = 0

u, x = 4 sin (u)

What is the general solution for cos(θ)=-(sqrt(11))/6 ?
The general solution for cos(θ)=-(sqrt(11))/6 is θ=2.15648…+2pin,θ=-2.15648…+2pin