What is the general solution for (2cos(x)-1)sin(x)=0 ?

The general solution for (2cos(x)-1)sin(x)=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x=2pin,x=pi+2pin

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(2cos(x)-1)sin(x)=0

(2 cos (x) - 1) sin (x) = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

(2 cos (x) - 1) sin (x) = 0

Solving each part separately

2 cos (x) - 1 = 0 or sin (x) = 0

2 cos (x) - 1 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = 2 πn, x = π + 2 πn

u, x = 4 sin (u)

2 cos (θ) = 2, 0 \leq θ < 2 π

cosh (θ) = 4 - j

\frac{1}{2} = tan (x)

7 sec (θ) = - 9.2

What is the general solution for (2cos(x)-1)sin(x)=0 ?
The general solution for (2cos(x)-1)sin(x)=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x=2pin,x=pi+2pin