What is the general solution for 0= pi/2-2arctan((pi/2-2-c)/(pi/2-c)) ?

The general solution for 0= pi/2-2arctan((pi/2-2-c)/(pi/2-c)) is No Solution for c\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0= pi/2-2arctan((pi/2-2-c)/(pi/2-c))

0 = \frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c})

No Solution for c \in R

Solution steps

0 = \frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c})

Switch sides

\frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c}) = 0

Move

\frac{π}{2}

to the right side

- 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c}) = - \frac{π}{2}

Divide both sides by

- 2

arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c}) = \frac{π}{4}

Apply trig inverse properties

\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c} = 1

Solve

\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c} = 1 :

No Solution for

c \in R

No Solution for c \in R

9 arcsin (x) = 3 π

2 sin (2 x + 10) - 3 = 0

cos (θ) = \frac{13}{6 \cdot 86}

\frac{1 + tan ( x )}{1 + cot ( x )} = 2

tan (x) + 1 = \frac{1}{3} + \frac{1}{3} cot (x)

What is the general solution for 0= pi/2-2arctan((pi/2-2-c)/(pi/2-c)) ?
The general solution for 0= pi/2-2arctan((pi/2-2-c)/(pi/2-c)) is No Solution for c\in\mathbb{R}