What is the general solution for sin(x)=-1/2 ,-pi<= x<= pi ?

The general solution for sin(x)=-1/2 ,-pi<= x<= pi is x=-(5pi)/6 ,x=-pi/6

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sin(x)=-1/2 ,-pi<= x<= pi

sin (x) = - \frac{1}{2}, - π \leq x \leq π

x = - \frac{5 π}{6}, x = - \frac{π}{6}

Solution steps

sin (x) = - \frac{1}{2}, - π \leq x \leq π

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

- π \leq x \leq π

x = - \frac{5 π}{6}, x = - \frac{π}{6}

- \frac{10 cos ( θ )}{3} = 10 sin (θ)

11 tan (c) + 6 = 3 tan (c) + 6

sin (x) = \frac{- 11}{11 2}

tan (x) = \frac{43}{45}

3 tan^{2} (x) + 5 tan (x) + 2 = 0

What is the general solution for sin(x)=-1/2 ,-pi<= x<= pi ?
The general solution for sin(x)=-1/2 ,-pi<= x<= pi is x=-(5pi)/6 ,x=-pi/6