What is the general solution for sin(2x+pi/3)=-(sqrt(3))/2 ?

The general solution for sin(2x+pi/3)=-(sqrt(3))/2 is x=pin+pi/2 ,x=pin+(2pi)/3

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sin(2x+pi/3)=-(sqrt(3))/2

sin (2 x + \frac{π}{3}) = - \frac{3}{2}

x = πn + \frac{π}{2}, x = πn + \frac{2 π}{3}

Solution steps

sin (2 x + \frac{π}{3}) = - \frac{3}{2}

General solutions for

sin (2 x + \frac{π}{3}) = - \frac{3}{2}

2 x + \frac{π}{3} = \frac{4 π}{3} + 2 πn, 2 x + \frac{π}{3} = \frac{5 π}{3} + 2 πn

Solve

2 x + \frac{π}{3} = \frac{4 π}{3} + 2 πn : x = πn + \frac{π}{2}

Solve

2 x + \frac{π}{3} = \frac{5 π}{3} + 2 πn : x = πn + \frac{2 π}{3}

x = πn + \frac{π}{2}, x = πn + \frac{2 π}{3}

tan (2 θ) + 2 cos (θ) = 0, 0 \leq θ \leq 2 π

cos (2 x) + 10 sin^{2} (x) = 5

2 = 3 + 2 sin (θ)

- 2 sin (θ) + sin (2 θ) = 0

- 2 sin^{2} (x) - 3 sin (x) + 2 = 0

What is the general solution for sin(2x+pi/3)=-(sqrt(3))/2 ?
The general solution for sin(2x+pi/3)=-(sqrt(3))/2 is x=pin+pi/2 ,x=pin+(2pi)/3