What is the general solution for -(10cos(θ))/(sqrt(3))=10sin(θ) ?

The general solution for -(10cos(θ))/(sqrt(3))=10sin(θ) is θ=(5pi)/6+pin

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-(10cos(θ))/(sqrt(3))=10sin(θ)

- \frac{10 cos ( θ )}{3} = 10 sin (θ)

θ = \frac{5 π}{6} + πn

Solution steps

- \frac{10 cos ( θ )}{3} = 10 sin (θ)

Rewrite using trig identities

10 tan (θ) = - \frac{10}{3}

Divide both sides by

10

tan (θ) = - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

11 tan (c) + 6 = 3 tan (c) + 6

sin (x) = \frac{- 11}{11 2}

tan (x) = \frac{43}{45}

3 tan^{2} (x) + 5 tan (x) + 2 = 0

sin (2 x + \frac{π}{3}) = - \frac{3}{2}

What is the general solution for -(10cos(θ))/(sqrt(3))=10sin(θ) ?
The general solution for -(10cos(θ))/(sqrt(3))=10sin(θ) is θ=(5pi)/6+pin