What is the general solution for cos^2(θ)+2cos(θ)=0 ?

The general solution for cos^2(θ)+2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^2(θ)+2cos(θ)=0

cos^{2} (θ) + 2 cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

cos^{2} (θ) + 2 cos (θ) = 0

Solve by substitution

cos (θ) = 0, cos (θ) = - 2

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos (θ) = - 2 :

No Solution

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

tan (x) = sec (x) - 3

3 sin (2 x) = 2 cos (2 x)

cos^{2} (θ) = 3 (1 - sin (θ))

cos (x) = \frac{13}{20}

sin^{2} (x) = 3 cos (x)

What is the general solution for cos^2(θ)+2cos(θ)=0 ?
The general solution for cos^2(θ)+2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin