What is the general solution for sin^2(θ)=sin(θ) ?

The general solution for sin^2(θ)=sin(θ) is θ= pi/2+2pin,θ=2pin,θ=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(θ)=sin(θ)

sin^{2} (θ) = sin (θ)

θ = \frac{π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

Solution steps

sin^{2} (θ) = sin (θ)

Solve by substitution

sin (θ) = 1, sin (θ) = 0

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

(7 sin (2 x) + 7 cos (2 x))^{2} = 49

- 1 - tan (x) = sec (x)

5 cos (θ) + 4 = 0

2 sin^{2} (2 θ) = - 1 + 3 sin (2 θ)

6 tan^{2} (θ) + 10 tan (θ) = 9 tan (θ) + 2

What is the general solution for sin^2(θ)=sin(θ) ?
The general solution for sin^2(θ)=sin(θ) is θ= pi/2+2pin,θ=2pin,θ=pi+2pin