What is the general solution for 5cos(θ)+4=0 ?

The general solution for 5cos(θ)+4=0 is θ=2.49809…+2pin,θ=-2.49809…+2pin

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5cos(θ)+4=0

5 cos (θ) + 4 = 0

θ = 2.49809 \dots + 2 πn, θ = - 2.49809 \dots + 2 πn

Solution steps

5 cos (θ) + 4 = 0

Move

4

to the right side

5 cos (θ) = - 4

Divide both sides by

5

cos (θ) = - \frac{4}{5}

Apply trig inverse properties

θ = arccos (- \frac{4}{5}) + 2 πn, θ = - arccos (- \frac{4}{5}) + 2 πn

Show solutions in decimal form

θ = 2.49809 \dots + 2 πn, θ = - 2.49809 \dots + 2 πn

2 sin^{2} (2 θ) = - 1 + 3 sin (2 θ)

6 tan^{2} (θ) + 10 tan (θ) = 9 tan (θ) + 2

y, z = cos (y)

cos (x) = \frac{64}{83}

2 sin (z) = 1

What is the general solution for 5cos(θ)+4=0 ?
The general solution for 5cos(θ)+4=0 is θ=2.49809…+2pin,θ=-2.49809…+2pin