What is the general solution for sin(θ)cos(θ)-2sin(θ)=0 ?

The general solution for sin(θ)cos(θ)-2sin(θ)=0 is θ=2pin,θ=pi+2pin

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sin(θ)cos(θ)-2sin(θ)=0

sin (θ) cos (θ) - 2 sin (θ) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

sin (θ) cos (θ) - 2 sin (θ) = 0

Factor

sin (θ) cos (θ) - 2 sin (θ) : sin (θ) (cos (θ) - 2)

sin (θ) (cos (θ) - 2) = 0

Solving each part separately

sin (θ) = 0 or cos (θ) - 2 = 0

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

cos (θ) - 2 = 0 :

No Solution

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

2 sin (2 x - \frac{π}{3}) = 1

sin (x) = \frac{15}{23}

4 sin^{2} (x) = 3, + [0, + 2 π]

6 sin (θ) - 1 = 4 sin (θ)

cot^{3} (x) = cot^{3} (x) sin (x)

What is the general solution for sin(θ)cos(θ)-2sin(θ)=0 ?
The general solution for sin(θ)cos(θ)-2sin(θ)=0 is θ=2pin,θ=pi+2pin