What is the general solution for 3sin(θ)+1=sin(θ) ?

The general solution for 3sin(θ)+1=sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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3sin(θ)+1=sin(θ)

3 sin (θ) + 1 = sin (θ)

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

3 sin (θ) + 1 = sin (θ)

Solve by substitution

sin (θ) = - \frac{1}{2}

sin (θ) = - \frac{1}{2} : θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Combine all the solutions

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

40 cos (\frac{2 π}{3} t) - 71 = - 80

- 2 cos (x) - 2 cos (2 x) = 0

tan (x) = 2 sin^{2} (x)

0 = 4 sin (2 x)

\frac{sin ( 112. 8 ^{\circ} )}{16.1} = \frac{sin ( x )}{12.2}

What is the general solution for 3sin(θ)+1=sin(θ) ?
The general solution for 3sin(θ)+1=sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin