What is the general solution for arccos(x)= 3/8 ?

The general solution for arccos(x)= 3/8 is x=cos(3/8)

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arccos(x)= 3/8

arccos (x) = \frac{3}{8}

x = cos (\frac{3}{8})

Solution steps

arccos (x) = \frac{3}{8}

Apply trig inverse properties

x = cos (\frac{3}{8})

2 sin^{2} (θ) - 3 sin (θ) = 0

\frac{cos ( x )}{1 + sin ( x )} + tan (x) = cos (x)

sin (2 x) = 2 cos^{2} (x), 0 \leq x \leq 2 π

2 sin (x) + 1 = cos (2 x)

sin (2 x) = - 1 sin (x)

What is the general solution for arccos(x)= 3/8 ?
The general solution for arccos(x)= 3/8 is x=cos(3/8)