What is the general solution for sin^3(x)=-sin^2(x) ?

The general solution for sin^3(x)=-sin^2(x) is x=2pin,x=pi+2pin,x=(3pi)/2+2pin

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sin^3(x)=-sin^2(x)

sin^{3} (x) = - sin^{2} (x)

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{3} (x) = - sin^{2} (x)

Solve by substitution

sin (x) = 0, sin (x) = - 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (θ) = \frac{4}{5}, sin (θ)

3 cos (2 θ) - 3 cos (θ) + 3 = 4 cos (θ) + 10

cos (x) = \frac{1}{18}

2 sin (2 x) cos (x) - sin (x) = 0

4 sin (\frac{θ}{2}) = 4 cos (\frac{θ}{2})

What is the general solution for sin^3(x)=-sin^2(x) ?
The general solution for sin^3(x)=-sin^2(x) is x=2pin,x=pi+2pin,x=(3pi)/2+2pin