What is the general solution for -10sin(2x)=0 ?

The general solution for -10sin(2x)=0 is x=pin,x= pi/2+pin

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-10sin(2x)=0

- 10 sin (2 x) = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

- 10 sin (2 x) = 0

Divide both sides by

- 10

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

sec (x) sin (x) - 3 sin (x) = 0, 0 \leq x \leq 36 0^{\circ}

cos (u) = \frac{5}{13}

4 sin (\frac{x}{2}) - 1 = 1

- sin (θ) = \frac{1}{2}

3 sec (θ) + 6 = 0

What is the general solution for -10sin(2x)=0 ?
The general solution for -10sin(2x)=0 is x=pin,x= pi/2+pin