What is the general solution for -sin(θ)= 1/2 ?

The general solution for -sin(θ)= 1/2 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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-sin(θ)= 1/2

- sin (θ) = \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

- sin (θ) = \frac{1}{2}

Divide both sides by

- 1

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

3 sec (θ) + 6 = 0

sin (x) - sin (x) \cdot cos (x) = 0, 0 \leq x \leq 2 π

8 sin (x) + 6 cos (x) = 8

4 sin (x) + 5 = 0

12 arctan (x) = 4 π

What is the general solution for -sin(θ)= 1/2 ?
The general solution for -sin(θ)= 1/2 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin