What is the general solution for sin(θ)=-0.15 ?

The general solution for sin(θ)=-0.15 is θ=-0.15056…+2pin,θ=pi+0.15056…+2pin

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sin(θ)=-0.15

sin (θ) = - 0.15

θ = - 0.15056 \dots + 2 πn, θ = π + 0.15056 \dots + 2 πn

Solution steps

sin (θ) = - 0.15

Apply trig inverse properties

θ = arcsin (- 0.15) + 2 πn, θ = π + arcsin (0.15) + 2 πn

Show solutions in decimal form

θ = - 0.15056 \dots + 2 πn, θ = π + 0.15056 \dots + 2 πn

2 cos (4 x) = 1

cos (2 x) = 2 sin (2 x)

4 cos^{2} (x) - 1 = 1

2 sin (θ) - 1 = 0

4 cos^{2} (x) + 5 cos (x) - 6 = 0

What is the general solution for sin(θ)=-0.15 ?
The general solution for sin(θ)=-0.15 is θ=-0.15056…+2pin,θ=pi+0.15056…+2pin