What is the general solution for sqrt(2)sin(θ)-1=0 ?

The general solution for sqrt(2)sin(θ)-1=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin

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sqrt(2)sin(θ)-1=0

2 sin (θ) - 1 = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Solution steps

2 sin (θ) - 1 = 0

Move

1

to the right side

2 sin (θ) = 1

Divide both sides by

2

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

4 cos^{2} (x) + 5 cos (x) - 6 = 0

3 cos (2 θ) = - 3 cos (θ)

csc^{2} (θ) + 3 csc (θ) + 2 = 0

cos^{2} (x) = 3 - 5 sin (x)

cos^{2} (θ) - sin^{2} (θ) = - 1

What is the general solution for sqrt(2)sin(θ)-1=0 ?
The general solution for sqrt(2)sin(θ)-1=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin