What is the general solution for cos^2(θ)-sin^2(θ)=-1 ?

The general solution for cos^2(θ)-sin^2(θ)=-1 is θ= pi/2+pin

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cos^2(θ)-sin^2(θ)=-1

cos^{2} (θ) - sin^{2} (θ) = - 1

θ = \frac{π}{2} + πn

Solution steps

cos^{2} (θ) - sin^{2} (θ) = - 1

Rewrite using trig identities

cos (2 θ) = - 1

General solutions for

cos (2 θ) = - 1

2 θ = π + 2 πn

Solve

2 θ = π + 2 πn : θ = \frac{π}{2} + πn

θ = \frac{π}{2} + πn

8 sin (\frac{x}{2}) + 8 cos (x) = 0

tan (\frac{θ}{2} + \frac{π}{6}) = 1

sec (x) = - 2, 0 < x < 2 π

1 - cos (2 x) = 0

sin (2 x) cos (x) = cos (x)

What is the general solution for cos^2(θ)-sin^2(θ)=-1 ?
The general solution for cos^2(θ)-sin^2(θ)=-1 is θ= pi/2+pin