What is the general solution for 10tan(b)+12=tan(b)+6 ?

The general solution for 10tan(b)+12=tan(b)+6 is b=-0.58800…+pin

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10tan(b)+12=tan(b)+6

10 tan (b) + 12 = tan (b) + 6

b = - 0.58800 \dots + πn

Solution steps

10 tan (b) + 12 = tan (b) + 6

Solve by substitution

tan (b) = - \frac{2}{3}

tan (b) = - \frac{2}{3} : b = arctan (- \frac{2}{3}) + πn

Combine all the solutions

b = arctan (- \frac{2}{3}) + πn

Show solutions in decimal form

b = - 0.58800 \dots + πn

arctan (x) + arctan (1 - x) = arctan (\frac{4}{3})

cos (θ) = \frac{- 8}{14 \cdot 20}

sin^{2} (x) = \frac{1}{3}

cot (x) = \frac{2}{3}

4 sin^{2} (x) + 1 = 2

What is the general solution for 10tan(b)+12=tan(b)+6 ?
The general solution for 10tan(b)+12=tan(b)+6 is b=-0.58800…+pin