What is the general solution for cot(x)+1=0,0<= x<2pi ?

The general solution for cot(x)+1=0,0<= x<2pi is x=(3pi)/4 ,x=(7pi)/4

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cot(x)+1=0,0<= x<2pi

cot (x) + 1 = 0, 0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Solution steps

cot (x) + 1 = 0, 0 \leq x < 2 π

Move

1

to the right side

cot (x) = - 1

General solutions for

cot (x) = - 1

x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

x, cos (k x) = - 1

sec^{2} (x) = \frac{3}{4}

sin (x) = \frac{4.4 sin ( 11 9 ^{\circ} )}{12.3}

- sec^{2} (x) = 2 tan (x)

3 cot^{2} (x) - 1 = 0

What is the general solution for cot(x)+1=0,0<= x<2pi ?
The general solution for cot(x)+1=0,0<= x<2pi is x=(3pi)/4 ,x=(7pi)/4