What is the general solution for -5tan(θ)-12=tan(θ)-8 ?

The general solution for -5tan(θ)-12=tan(θ)-8 is θ=-0.58800…+pin

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-5tan(θ)-12=tan(θ)-8

- 5 tan (θ) - 12 = tan (θ) - 8

θ = - 0.58800 \dots + πn

Solution steps

- 5 tan (θ) - 12 = tan (θ) - 8

Solve by substitution

tan (θ) = - \frac{2}{3}

tan (θ) = - \frac{2}{3} : θ = arctan (- \frac{2}{3}) + πn

Combine all the solutions

θ = arctan (- \frac{2}{3}) + πn

Show solutions in decimal form

θ = - 0.58800 \dots + πn

\frac{1}{4} sin (4 t) = 0

csc (x) + 2 = 0, (0, 2 π)

2 cos (4 x) = 2 cos^{2} (2 x) - sin (2 x) - 1

x, sin (x - 4 0^{\circ}) = cos (y - 2 0^{\circ})

0 = - sin (2 x)

What is the general solution for -5tan(θ)-12=tan(θ)-8 ?
The general solution for -5tan(θ)-12=tan(θ)-8 is θ=-0.58800…+pin